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Integration - Building Totals from Rates of Change

Integration is the reverse of differentiation. If differentiation breaks things apart to find rates of change, integration builds them back together to find totals – areas, volumes, accumulated quantities. Integration is one of the most powerful tools in all of mathematics and science.

Two Types of Integration

Indefinite integrals find a general family of functions (always including + C).
Definite integrals calculate a specific numerical value – the net area between a curve and the x-axis over a given interval.

The Antiderivative

The integral of f(x) is a function F(x) such that F′(x) = f(x). It is called the antiderivative.
Notation: ∫ f(x) dx = F(x) + C
The constant C appears because many functions share the same derivative – for example, x², x²+5, and x²−100 all differentiate to 2x.

Basic Integration Rules

Function f(x)Integral ∫f(x) dx
xn (n ≠ −1)xn+1 / (n+1) + C
1/xln|x| + C
exex + C
sin x−cos x + C
cos xsin x + C
sec² xtan x + C
k (constant)kx + C

The Fundamental Theorem of Calculus

This theorem is the bridge between differentiation and integration. It has two parts:
Part 1: If F(x) = ∫ax f(t) dt, then F′(x) = f(x). Differentiation undoes integration.
Part 2:ab f(x) dx = F(b) − F(a), where F is any antiderivative of f.
Part 2 is the practical rule you use to evaluate definite integrals.

Worked Examples

Find ∫ (3x² + 4x − 5) dx.

Integrate term by term:
∫ 3x² dx = x³,   ∫ 4x dx = 2x²,   ∫ −5 dx = −5x.
Answer: x³ + 2x² − 5x + C.

Evaluate ∫13 (2x + 1) dx.

Antiderivative: F(x) = x² + x.
F(3) − F(1) = (9 + 3) − (1 + 1) = 12 − 2 = 10.

Find the area under y = x² between x = 0 and x = 3.

03 x² dx = [x³/3]03 = 27/3 − 0 = 9 square units.

Find ∫ sin(2x) dx.

Use reverse chain rule. The antiderivative of sin(u) is −cos(u); the inner derivative of 2x is 2.
∫ sin(2x) dx = −cos(2x)/2 + C.

Integration by Substitution

When an integrand contains a composite function, substitute u = g(x) to simplify it.
Steps: 1. Choose u = inner function.   2. Find du/dx and write dx = du / g′(x).   3. Rewrite the integral in terms of u.   4. Integrate.   5. Back-substitute x.

Find ∫ 2x(x² + 1)4 dx.

Let u = x² + 1. Then du = 2x dx.
∫ u4 du = u5/5 + C = (x²+1)5/5 + C.

Key Takeaways

  • Integration is the reverse of differentiation.
  • Power rule: ∫ xn dx = xn+1/(n+1) + C (n ≠ −1).
  • Definite integral = F(b) − F(a) = exact area under the curve from a to b.
  • Always add + C to indefinite integrals.

Practice Questions

  1. Find ∫ (5x4 − 6x + 3) dx.
  2. Evaluate ∫02 (x² + 2) dx.
  3. Find the area under y = 3x² between x = 1 and x = 4.
  4. Find ∫ cos(4x) dx.
  5. Use substitution to find ∫ 3x²(x³ + 5)6 dx.
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