Cube of a Binomial — (a + b)³
Just like (a + b)² can be seen as a square split into four area pieces, (a + b)³ can be seen as a cube split into eight volume pieces. This page lets you explore that cube directly: rotate it, then move each piece across one at a time to watch the formula build itself up.
(a + b)³ = a³ + 3a²b + 3ab² + b³
Splitting the Cube
Take a cube whose every edge is (a + b) long. Split each of its three edges — length, width and height — into an a-part and a b-part. That divides the whole cube into a 2×2×2 grid of 8 smaller boxes:
- 1 box of size a×a×a — volume a³
- 3 boxes of size a×a×b (one for each pair of edges) — volume a²b each
- 3 boxes of size a×b×b — volume ab² each
- 1 box of size b×b×b — volume b³
Add up all 8 volumes and nothing has been added or removed from the original cube — only cut apart — so a³ + 3a²b + 3ab² + b³ must equal the same volume as the whole cube, (a + b)³.
Try It Yourself
Drag either cube with your mouse to rotate it and look at it from any angle. Then click a piece in the left cube to send it into its matching empty slot on the right — the dashed outline always shows you exactly which piece is missing from the left cube and which one has arrived on the right.
One a³, one b³, and three matching copies each of a²b and ab² — that's where the 3a²b and 3ab² come from.
Why This Proves the Identity
Nothing about cutting a solid into pieces and moving them around changes their total volume. The 8 boxes above are exactly the same material as the original (a + b)³ cube, just relabelled by which edge-part (a or b) each one occupies along each direction. So:
(a + b)³ = a³ + a²b + a²b + a²b + ab² + ab² + ab² + b³ = a³ + 3a²b + 3ab² + b³
(2 + 1)³ = 3³ = 27. And 2³ + 3(2²)(1) + 3(2)(1²) + 1³ = 8 + 12 + 6 + 1 = 27. ✓
Practice: Cube of a Binomial
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